Math 216: Statistical Thinking
The probability of the intersection of two events, \(A\) and \(B\), can be calculated using the multiplicative rule. This rule uses conditional probabilities:
\[ P(A \cap B) = P(A) \cdot P(B|A) \]
Alternatively:
\[ P(A \cap B) = P(B) \cdot P(A|B) \]
Interpretation: The rule helps us understand how the occurrence of one event influences the probability of another.
The law of total probability allows us to calculate the probability of an event by considering all possible scenarios. For two mutually exclusive and exhaustive events \(B\) and \(B^c\):
\[ P(A) = P(B) \cdot P(A|B) + P(B^c) \cdot P(A|B^c) \]
Application: This is particularly useful when dealing with partitioned sample spaces.
Special case where knowledge of one event doesn’t affect another’s probability:
\[ P(A|B) = P(A) \quad \text{and} \quad P(B|A) = P(B) \]
Simplified Intersection Rule:
\[ P(A \cap B) = P(A) \cdot P(B) \]
Caution: Independence requires mathematical proof, not visual intuition from Venn diagrams
Derived from multiplicative rule symmetry:
\[ P(A|B) = \frac{P(A) \cdot P(B|A)}{P(B)} \]
Enhanced with total probability law:
\[ P(A|B) = \frac{P(A)P(B|A)}{P(A)P(B|A) + P(A^c)P(B|A^c)} \]
Enables belief updating with new evidence
Objective: Calculate \(P(A | B)\) - disease probability given alcoholism
Bayesian Calculation:
\[P(A | B) = \frac{P(A)P(B|A)}{P(B)} = \frac{0.10 \cdot 0.07}{0.05} = 0.14\]
Interpretation: Alcoholism doubles disease risk compared to baseline (10% → 14%)